On a certain hot summer's day, 391 people used the public swimming pool. the daily prices are $1.25 for children and $2.25 for adults. the receipts for admission totaled $752.75. how many children and how many adults swam at the public pool that day?

127 children and 264 adults swam at the public pool that day

Solution:

Let "c" be the number of children swam

Let "a" be the number of adult swam

Cost for each children = $ 1.25

Cost for each adult = $ 2.25

391 people used the public swimming pool

Therefore,

c + a = 391

a = 391 - c ------- eqn 1

The receipts for admission totaled $752.75

Therefore, we frame a equation as:

number of children swam x Cost for each children + number of adult swam x Cost for each adult = 752.75

1.25c + 2.25a = 752.75 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

1.25c + 2.25(391 - c) = 752.75

1.25c + 879.75 - 2.25c = 752.75

c = 879.75 - 752.75

c = 127

Substitute c = 127 in eqn 1

a = 391 - 127

a = 264

Thus 127 children and 264 adults swam at the public pool that day

answer is 33

step-by-step explanation:

idk what the heck he answer is, i’m just putting this here so i finish my account