What quantity of 78% chlorine solution must be mixed with a 23% chlorine solution to produce 477.16 ml of 60% solution?

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

Step-by-step explanation:

Let

x ----> quantity of 78% chlorine solution in milliliters

y ----> quantity of 23% chlorine solution in milliliters

we know that

The quantity x of 78% chlorine solution mixed with a quantity y of 23% chlorine solution produce 477.16 mL of 60% solution

so

----> equation A

----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (321, 156.16)

therefore

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

b

step-by-step explanation: