The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert. they make $3 from each student ticket and $5 from each adult ticket. let x represent the number of student tickets, and let y represent the number of adult tickets. which linear inequality can be used to find the combinations of adult and student tickets that they can sell to meet their goal?

The linear inequality form is .

Step-by-step explanation:

Given : The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert. They make $3 from each student ticket and $5 from each adult ticket.

To find : Linear inequality can be used to find the combinations of adult and student tickets that they can sell to meet their goal?          

Solution :

Let x represent the number of student tickets.

Let y represent the number of adult tickets.

Cost of ticket per student = $3

Cost of ticket of students = 3x

Cost of ticket per adult student = $5

Cost of ticket of adult students = 5x

The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert.

i.e, minimum $800 is the least amount

The linear inequality form is .

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )