Wyatt's eye-level height is 120 ft above sea level, and shawn's eye-level height is 270 ft above sea level. how much farther
can shawn see to the horizon? use the formula d=square root 3h/2, h less than equal too 0, with d being the distance they can see in miles and h being
their eye-level height in feet.

The answer is 3√5 mi.

The formula is: d = √(3h/2)

Wyatt:

h = 120 ft

d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?

Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )