Assume that a study of 500 randomly selected airplane routes showed that 482 arrived on time. select the correct interpretation of the probability of an airplane arriving late. interpret an event as significant if its probability is less than or equal to 0.05.
a. significant at 0.0036
b. not significant at 0.964
c. significant at 0.036
d. not significant at 0.036

C. Significant at 0.036

Step-by-step explanation:

Given:

Number of selected samples Ns= 500

Number of airplane that arrive on time Na = 482.

Number of airplane that arrive late Nl = 500 - 482 = 18

The probability that an airplane arrive late:

P(L) = Nl/Ns

P(L) = 18/500

P(L) = 0.036

Interpret an event as significant if its probability is less than or equal to 0.05.

Since P(L) < 0.05

P(L) = Significant at 0.036

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: