Mathematics, 29.01.2020 03:49 cbrewer37
What is the repulsive force between two pith balls that are 12.0 cm apart and have equal charges of −27.0 nc?
Answers: 2
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![F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-27\times10^{-9}C)^2}{[(12 cm)(\frac{1m}{100cm} )]^2}](/tpl/images/0480/0953/2d572.png)
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