Algebra 2b u2 l6 function operations practice #4-7

let g(x) = 2x and h(x)= x^2 +4. find the value.

4 (h•g)(1)

a 2
b 8
c 10
d 16

5 (g•h)(0)

a 4
b 8
c 0
d 16

6 (h•)

a 31
b 58
c 77
d 104

7 (h•g)(a)

a 4a^2+a
b 2a^3+8
c 4a^2+8a
d 4a^2+4

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

Idon’t exactly understand but i think dbc=rst