Explain why the following sets of vectors are not basis for the indicated vector spaces. (solve this problem by inspection.)
(a) u1 = (1, 2), u2 = (0, 3), u3 = (2, 7) for r^2
(b) u1 = (-1, 3, 2), u2 = (6, 1, 1) for r^3

a.This set of vectors are not basis for vector space for two-dimentional space R2 due to high number of vectors (3). It means three vector is two much to span 2-dimentional space.

b.This set of vectors are not basis for vector space for three-dimentional space R3 due to small number of vectors (2). It means two vector can't span three-dimentional space.

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x