Delta airlines quotes a flight time of 2 hours, 5 minutes for its flights from cincinnati to tampa. suppose we believe that actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes. what is the probability that the flight will be no more than 5 minutes late?

 0.5

Step-by-step explanation:

Given : Delta Airlines quotes a flight time of 2 hours, 5 minutes for its flights from Cincinnati to Tampa.

i.e. Flight time =   2(60) +5= 125 minutes  [∵ 1 hour = 60 minutes]

Actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes.

i.e. In minutes the flight times are between 120 minutes and 140 minutes.

Let x be a uniformly distributed variable in [120 minutes, 140 minutes] that  represents the flight time.

Since the probability density function for x uniformly distributed in [a,b] is

⇒ Probability density function for flight time  :

5 minutes late than usual time = Flight time+ 5 = 125+5 = 130 minutes

Now , the probability that the flight will be no more than 5 minutes late will be :-

Hence, the probability that the flight will be no more than 5 minutes late is 0.5.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

source