Y= 1/(x² + c)
is a one-parameter family of solutions of the first-order de y' + 2xy² = 0.
find a solution of the first-order ivp consisting of this differential equation and the given initial condition. give the largest interval i over which the solution is defined.

Step-by-step explanation:

We are given that one parameter family of solution of the first order DE

DE

Substitute x=2

Substitute the value of c

Solution is defined for all  values of x except x=

Therefore, by unique existence theorem

The largest interval on which the solution is defined

it is x=-4

step-by-step explanation:

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )