Mathematics, 28.08.2019 15:30 karenjjensen
Ayoung equestrian loved to ride her horse all day long, dreaming of the day she would ride in the kentucky derby. one day in early april, she left home at 10: 00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. at noon a call came in from the derby saying she was in! her father immediately jumped on his scooter to try and track her down and tell her the good news. riding at a breezy 15 miles per hour, at what time will her father catch up to her? what is a reasonable first step in solving this problem?
Answers: 2
Mathematics, 21.06.2019 22:00, juniorracer148
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
Ayoung equestrian loved to ride her horse all day long, dreaming of the day she would ride in the ke...
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