Tamara is creating a model of a rectangle. she has 26 inches of yellow ribbon to use for the border of the rectangle. she wants the length, l, to be 3 inches greater than the width, w. which system of equations could tamara use to find the dimensions of a rectangle that uses all of the ribbon?

System of equations are l = w + 3 and 2(l + w) = 26

Step-by-step explanation:

Tamara is creating a model of a rectangle.

She has yellow ribbon of length = 26 inches.

If the length of the rectangle is l and width of the rectangle is w then as per statement of the question

l = (w + 3) (1)

Now we form an equation of perimeter with given dimensions

Perimeter P = 2(length + width) ⇒ 2(l + w) = 26 (2)

Therefore system of two equations which can be solved to get the dimensions of the rectangle.

l = (w + 3) & 2(l + w) = 26

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.