You are giving 24 linear feet of fencing all 3 feet tall you wish to make the largest rectangular enclosure possible to maximize space what should the dimensions of the enclosure be

The largest area enclosed is  A = xy = 6 feet 6 feet = 36

Step-by-step explanation:

i) The perimeter of the area is 2(x + y) =24  ∴ x + y = 12    ∴ y = 12 - x

ii) The area of rectangle enclosed A  = xy    ⇒ A  = x ( 12 - x) = 12x -

iii) differentiating both sides of the equation in ii) we get

   ⇒  x = 6 feet

iv) Differentiating both sides of equation in iii) we get     =  -2

   Therefore the area enclosed is maximum as the double derivative is negative

v) therefore for largest area enclosed   x  = 6 feet and  y = 12 - 6 = 6 feet

vi) therefore the largest area enclosed is

 A = xy = 6 feet 6 feet = 36

the correct answer is the second option

f(x) = y

f(-3) = -5

step-by-step explanation: