Suppose that a newspaper predicted that candidate a would defeat candidate b in a certain election. they conducted a poll of telephone directories with a response rate of 24%. on the basis of the results, the newspaper predicted that candidate a would win with 57% of the popular vote. however, candidate b won the election with about 62% of the popular vote. at the time of this poll, most households with telephones belonged to the party of candidate a. name two biases that led to this incorrect prediction.
a. sampling bias: using an incorrect frame led to under-coverage.
response bias: the way the poll was administered showed bias.
b. non-response bias: the low response rate caused bias.
sampling bias: using an incorrect frame led to undercoverage.
c. non-response bias: the low response rate caused bias.
response bias: the way the poll was administered showed bias.

B, non response bias, and sampling bias

Step-by-step explanation:

Non response bias is when there is a huge difference between people that responded or took part in the polls and people that didn't respond, since we are told the response rate was 24% and sampling bias because it is said that most people using telephones belong to the party of candidate A, so using a telephone poll makes the sampling biased

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

a

step-by-step explanation: