Jon's dog weighs ( v ) pounds. his cat weighs 21 pounds less than his dog. his bunny weighs 3 pounds less than his cat? what is the weight of jon's pets?

the weight of Jon's pet is

(3v - 25) pounds

Step-by-step explanation:

The weight of Jon's dog is v pounds.

His cat weighs 21 pounds less than his dog. It means that the weight of his cat would be

(v - 21) pounds

His bunny weighs 3 pounds less than his cat. It means that the weight of his bunny would be

(v - 21) - 3 = (v - 24) pounds

Therefore, the weight of Jon's pets would be the sum of the weight of his dog, his cat and his bunny. It becomes

v + v - 21 + v - 24 = (3v - 25) pounds.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )