If the volume of the crystal ball is about 113 14 cm", the radius of the ball is approximately 3 cm. (use = 7.)
if the vacant space inside the box were filled with spray foam, the approximate volume of foam required would
cm^3.

The volume of required foam is 0.1 cm³  

Step-by-step explanation:

Given as :

The volume of box = v = 113.14 cm³

The radius of the crystal ball = r = 3 cm

Let The volume of required foam = V cm³

According to question

Volume of  crystal ball = × π × radius³                        where π = 3.14

i.e Volume of ball = × π × 3³

Or, Volume of ball = × π × 27

Or, Volume of ball = × 3.14 × 27

Or, Volume of ball = 4 × 3.14 × 9

Or, Volume of ball = 113.04 cm³

Again

∵ volume of crystal ball = v' = 113.04 cm³

So ,  The volume of required foam = volume of box - volume of crystal ball

Or, V =  v - v'

Or, V = 113.14 cm³ -  113.04 cm³

∴   V = 0.1 cm³

So, The volume of required foam = V = 0.1 cm³

Hence, The volume of required foam is 0.1 cm³  . Answer

3.4 pizzas

step-by-step explanation:

given is a scatter plot showing number of pizzas sold during weeks for different issues of coupon

y represents number of pizzas sold and x number of coupons issued

y is marked verticaly and x horizontally

the trend line is given as

y =3.4x+43

this says that even when no coupon is issued pizzas sold will be 43

and rate of change of pizza sold for 1 unit of coupon = slope = 3.4

i.e. when x increases by 1 unit y increases by 3.4 units

hence for each additional coupon issued 3.4 pizzas more will be sold

jjhjhhjjh

step-by-step explanation: