How much greater is the area of a circle with a radius of 6.2 inches than the area of a square with a side length of 4 inches?

7.54 times greater.

Step-by-step explanation:

The square with a side length of 4 inches has a 4×4=16 inches squared area. The area of a cirkel is calculated with the formula \pi×r^2. Using the 6.2 inch radius given, we get \pi×6.2^2=120.76 inches squared. 120.76/16=7.54 times greater.

step-by-step explanation:

if x = 2 you have to find x to finish the problem

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: