Ineed with this math problem.

the volume v of a pyramid with a square base with side length s and height h is v=1/3s^2h. solved for s, this formula gives s= startroot startfraction 3 upper v over h endfraction endroot . a pyramid has a volume of approximately 7,500,000 cubic meters. find the length of the side of the pyramid if its height is approximately 141 meters.
here's a picture of the problem since i'm not able to write the equation out like its shown.

The answer to your question is s = 399.5 m

Step-by-step explanation:

Formula

Data

V = 7 500 000 m³

h = 141 m

Substitution

                 s = 399.46 meters ≈ 399.5 meters

s = 400 meters

Step-by-step explanation:

The volume V of a pyramid with a square base with side length s and height h is

V=1/3s^2h

Solved for s, this formula gives

s = √3V/h

Given that the pyramid has a volume, V of approximately 7500000 cubic meters and the height is approximately 141 meters, the length if the side of the pyramid, s would be

s = √3 × 7500000/141

s = √3 × 53191.4894

s = √159574.4682

s = 399.468

s = 400 meters approximated to the nearest meter

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.