Aseed company planted a floral mosaic of a national flag. the perimeter of the flag is 2,160 ft determine the flag's width and length if the length is 440 ft greater than the width.

The length of flag is 760 feet and width of flag is 320 feet

Solution:

A seed company planted a floral mosaic of a national flag

Since, the flag is generally of shape rectangle, we can use the formula of rectangle

Let "a" be the length of rectangle

Let "b" be the width of rectangle

The length is 440 ft greater than the width

Length = 440 + width

a = 440 + b eqn 1

The perimeter of the flag is 2,160 ft

The perimeter of rectangle is given as:

Perimeter = 2(length + width)

Substituting the given values, we get

2160 = 2(440 + b + b)

2160 = 880 + 4b

4b = 2160 - 880

4b = 1280

b = 320

Substitute b = 320 in eqn 1

a = 440 + 320

a = 760

Thus the length of flag is 760 feet and width of flag is 320 feet

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

a rotation about point l

step-by-step explanation:

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