With a short time remaining in the day, a delivery driver has time to make deliveries at 66 locations among the 99 locations remaining. how many different routes are possible? there are possible different routes. (simplify your answer.)

197,443,926,105,102,399,225,573,693

Step-by-step explanation:

Here we use combination which is the selection of all or part of a set of objects or items without considering the order of selection.

Mathematically, The number of 'r' combinations from 'n' elements is given as :

nCr = n!÷((n-r)!r!)

From the question above :

n=99 r=66

99C66 = 99!÷((99-66)!66!)

99!÷(33!66!) = 197,443,926,105,102,399,225,573,693

There are 197,443,926,105,102,399,225,573,693 different possible routes.

the answer is 288..

hope this

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !