⇒how many solutions does the equation 10-3x +10x-7=5x-5+2x+8 have? a. one solution b. two solutions c. no solutions d. infinitely many solutions

d. Infinitely many solutions

Step-by-step explanation:

The given equation is expressed as

10-3x +10x-7 = 5x-5+2x+8

The first step is to make all the terms containing the variable to be on the left hand side of the equation and the constants to be on the right hand side of the equation.

10-3x +10x-7=5x-5+2x+8

10 - 7 + 10x - 3x = 5x + 2x - 5 + 8

7x + 3 = 7x + 3

Subtracting 7x and 3 from the left hand side and the right hand side of the equation, it becomes.

7x - 7x + 3 - 3 = 7x - 7x + 3 - 3

0 = 0

It has infinitely many solutions because as any value of x would satisfy both sides of the equation.

b is the answer that makes most sense

step-by-step explanation: