The zeros of a quadrtic function are located at (3, 0) and (-4, 0). which product shows the linear factors of this function's equation?
(x + 3)(x + 4)
(x - 3)(x + 4)
(x - 3)(x - 4)
(x + 3)(x - 4)

This one is pretty simple. You have to look at the zeros given to you and you just have to plug it in for X. For the first function, (X+3(X+4), you replace the Xs so it would look something like this. (3+3)(-4+4). When you solve for both of these you will get 6 and 0. Because they both do not equal out to zero, this function does not work. If you do that to the rest of the functions, you will find that (X-3)(X+4) will equal out to 0 for both. You then know that this is the function. You can make sure that that is the correct answer by plugging the zeros into the other functions as well. If you do so, you will find that the other functions do not work.

A’b’c’ are the coordinates to the new location of the transformed triangle abc. find the distance between the coordinates points to use for your calculations.