Two physics students are doing a side competition during a game of bowling, seeing who can toss a ball with the larger momentum. the first bowler throws a 4.5 kg ball at 8.6 m/s. part a a second bowler throws a 6.4 kg ball. what speed must she beat to win the competition?

she should beat a speed of  v₂ = 6.04 m/s in order to win the competition

Step-by-step explanation:

Since the momentum p is defined as

p = m*v

where

m= mass of the ball

v= velocity of the ball

denoting 1 and 2 as the first and second bowler , then to reach the momentum of the first bowler

p₂=p₁

therefore

m₁*v₁ = m₂*v₂

v₂ = v₁ * (m₁/m₂)

replacing values

v₂ = v₁ * (m₁/m₂) =8.6 m/s * (4.5 kg/6.4 kg ball) = 6.04 m/s

then since the momentum p = m*v increases with increasing v (at constant m)  , she should beat a speed of  v₂ = 6.04 m/s in order to win the competition

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

b, 20 yards

step-by-step explanation: