In a class of 26 students, 15 of them like maths, 13 of them like english and 9 of them like neither. find the probability that a student chosen at random likes english but not maths.

venn diagram doesn't need to be completed,, some working out would because this is exam revision.

0.0769

Step-by-step explanation:

Let x be the number of student that offer both subjects

15 - x + x + 13 - x + 9 = 26

-x + 37 = 26

-x = -11

x = 11

Number of student that offer english but not math = 13 - 11

                                                                                        = 2

The probability of english but not math = 2/26

The probability that a student is chosen at random likes English but not maths is .

Given information:

In a class of 26 students, 15 of them like maths, 13 of them like English and 9 of them like neither.

Now, the number of students who like either maths or English will be,

Now, out of 17, 15 students like maths and 13 students like English.

So, the number of students who like both the subjects will be,

Now, 11 students like both the subjects and 13 students like English.

So, the number of students who like English but not maths will be,

Thus, the probability that a student chosen at random likes English but not maths will be calculated as,

Therefore, the probability that a student is chosen at random likes English but not maths is .

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50x5=$250

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1