Ms. davis teaches jewelry making at the community college. each of her 25 students will need 1eleven-twelfths feet of leather cord to make necklaces. the cord is sold in 5-foot spools, and she cannot purchase a partial spool. which equation would provide the best estimate of how many spools of cord she needs to buy?

The equation that would provide the best estimate of how many spools of leather cord Ms. Davis needs to buy is:

x = (s * l)/5, where s = 25 and l = 1

Step-by-step explanation:

1. Let's review the information provided to us to help Ms. Davis to answer the question correctly:

Number of students at Ms. Davis jewelry making class = 25

Leather cord each student will need to make necklaces = 11/12 feet

Leather cord is sold in 5-foot spools

2. Which equation would provide the best estimate of how many spools of cord she needs to buy?

Number of 5-foot spools Ms Davis needs to buy = x

Number of students = s

For avoiding issues with the leather cord length per student, it's better to estimate 1 feet per student because with 11/12 feet it always will give Ms Davis partial amounts. Therefore,

Length of leather cord per student = l = 1 feet

Now we can write the equation, this way:

x = (s * l)/5

Replacing with the real values, we have:

x = (25 * 1)/5 = 25/5 = 5 5-foot spools of leather cord

The equation that would provide the best estimate of how many spools of cord Ms. Davis needs to buy is

x = (s * l)/5, where s = 25 and l = 1

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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