In a psychology class, 32 students have a mean score of 93.2 on a test. then 16 more students take the test and their mean score is 63.4.what is the mean score of all of these students together? round to one decimal place. mean of the scores of all the students =

 83.3

Step-by-step explanation:

Formula :

                  (1)

          (2)

Given : In a psychology class, 32 students have a mean score of 93.2 on a test.

By Using (2) , Sum of scores of 32 students = 93.2 x 32 =2982.4   (3)

Then 16 have a mean score of 63.4.

Again, By Using (2) , Sum of scores of 16 students = 63.4 x 16 =1014.4   (4)

Total students = 32+16 = 48

Add (3) and (4) , we get combined score of 48 students = 2982.4+ 1014.4

=3996.8

Now , by using (2) , the  mean score of all of these students together

Hence, the mean score of all of these students together is 83.3.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .