(! ) two buses leave the bus station at 8 am. if bus #1 makes its route in a total of 60 minutes and bus #2 makes its route in a total of 80 minutes, at what time will the two buses meet again?

  12 pm noon

Step-by-step explanation:

The least common multiple of the two times is 240 minutes, or 4 hours. The buses will meet at the station again at noon.

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60 = 20×3

80 = 20×4

The least common multiple is 20×3×4 = 240 minutes. There are 60 minutes in an hour, so this is 240/60 = 4 hours. 4 hours after 8 am is 12 pm, noon.

im sorry but no. i just need to answer for 50 poonts oof

x/3-10=8

x/3=18

x=48