Abby has a collection of 61 dimes and nickels worth $4.40. how many nickels does she have? show steps

  34 nickels

Step-by-step explanation:

First, consider the value if they were all dimes. That would be 61×$0.10 = $6.10. Next, realize this is more than the actual amount by 1.70. Of course, replacing one of the 61 dimes by a nickel reduces the total amount by $.05, so we must have ...

  $1.70/$0.05 = 34

nickels in the mix.

Abby has 34 nickels.

Alternate solution methods

I like to solve these using number sense, as above. Equivalently, an equation can be written using n to represent the number of nickels. The total value is then ...

  .05n + .10(61 -n) = 4.40

  -.05n +6.10 = 4.40 . . . . . . eliminate parentheses

  -.05n = -1.70 . . . . . . . . . . . subtract 6.10

  n = -1.70/-.05 = 34

Hopefully, you notice some similarities between this solution and the one in words, above.

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Often, you will see this sort of problem formulated using two equations.

  n + d = 61 . . . . . . . . . . number of coins (d=#of dimes)

  .05n +.10d = 4.40 . . . .value of coins

If we solve this by substitution, we can use d=61-n, and get ...

  .05n +.10(61-n) = 4.40 . . . . . . looks like our equation in the previous section

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.