Aquadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. how many real number solutions does the equation have?

The quadratic equation have no real roots.

Step-by-step explanation:

We are given that,

The discriminant of the quadratic equation is -16.

We know that,

If in a quadratic equation,

, the equation have real and distinct roots.

, the equation have real and equal roots.

, the equation have no real roots.

Since, the discriminant of the equation is -16 < 0.

Thus, the quadratic equation have no real roots.

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.