Ametalworker has a metal alloy that is 20% copper and another alloy that is 70% copper. how many kilograms of each alloy should the metalworker combine to create 100 kg of a 50% copper alloy?

40 kilograms alloy of 20 % copper and 60 kilograms of alloy of 70 % copper is combined to get 100 kg of 50 % copper alloy

Solution:

Th final alloy is 100 kg

Let "x" be the alloy of 20 % copper

Then, (100 - x) is the alloy of 70 % copper

Therefore,we can say,

"x" kilograms alloy of 20 % copper and (100 - x) kilograms of alloy of 70 % copper is combined to get 100 kg of 50 % copper alloy

Therefore, we frame a equation as:

Thus 40 kilograms of 20 % copper

Then, 100 - x = 100 - 40 = 60

60 kilograms of 70 % copper is used

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: