Choose an american household at random, and let the random variable x be the number of cars (including suvs and light trucks) they own. here is the probability model if we ignore the few households that own more than 6 cars:

number of cars x probability 0 1 2 3 4 5 6

0.07 0.31 0.43 0.12 0.04 0.02 0.01

a housing company builds houses with two-car garages. what percent of households have more cars than the garage can hold?

19% of households have more cars than the garage can hold

Step-by-step explanation:

We are given the following distribution for the number of cars owned by a family.

Number of cars X:        0        1           2        3           4          5          6

Probability:                0.07    0.31     0.43    0.12     0.04     0.02    0.01

We have to find the percentage of households have more cars than the garage can hold.

A garage can hold two cars. Thus, the household with more than two cars are the households that  have more cars than the garage can hold.

The given distribution is a discrete probability distribution.

Thus, we evaluate:

Thus, 19% of households have more cars than the garage can hold.

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23