Apomegranate is thrown from ground level straight up into the air at time t=0 with velocity 32 feet per second. its height at time t seconds is f(t)=−16t2+32t. find the time tg it hits the ground and the time th it reaches its highest point. what is the maximum height h? enter the exact answers.

It hit the ground at t=2

It reaches its highest point at t=1

Its maximum height =16

Step-by-step explanation:

The graph of the function of the height will be a parapola opening downward where it's x intercepts = the time where the object hit the ground and its maximum point = the point with the maximum point

The x intercepts are 0 when the object was thrown and 2 when it landed

The x coordinate of the vertex is in the middle of the two x intercepts so it will be 1

Substituting the x coordinate of the vertex gives us the y coordinate of the vertex which is the maximum hight 16

a. 19,958,400

step-by-step explanation:

hope this

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap