paul has $35000 to invest. his intent is to earn 11% interest on his investment. he can invest part of his money at 8%
interest and part at 14% interest. how much does paul need to invest in each option to make get a total 11% return on
his $35000?
investing for 8% return: $
9
investing for 14% return: $
b

Step-by-step explanation:

The fraction that needs to be invested at the higher rate is ...

  (11% - 8%)/(14% -8%) = 3%/6% = 1/2

Half the money should be invested at each of the rates:

  $17,500 for 8% return

  $17,500 for 14% return.

If you let x represent the amount at the higher rate, then the total return is ...

  14%x + 8%(35000 -x) = 11%(35000)

  (14% -8%)x = (11% -8%)(35000) . . . . subtract 8%·35000

  x = (11% -8%)/(14% -8%)×35000 . . . . divide by the coefficient of x

Note that this formula is exactly the one we started with, above.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

u dumb boi

step-by-step explanation: