How many liters of a 20% solution of acid should be added to 10 liters of a 30% solution of acid to obtain a 25% solution?

liters

10 urgent points

plz

10 liters

Step-by-step explanation:

Let

x ----> liters of a 20% solution of acid

we know that

The number of liters of a 20% solution of acid, multiplied by 0.20 (20% in decimal form) plus 10 liters of a 30% solution of acid multiplied by 0.30 (30% in decimal form) must be equal to the amount of (x+10) liters multiplied by 0.25 (25% in decimal form)

so

The linear equation that represent this problem is equal to

solve for x

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i dont know men

step-by-step explanation: