Referring to the figure, use fraction pieces of 1/3 and 1/6 to form a fraction mat equal to 1.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

figure c

step-by-step explanation:

hope this .