Afarmer has a rectangle field with a perimeter of 5.4 miles and a length of 2.3 miles. find the width of the field. the width of the rectangle with perimeter p in length l is given by w equals p -2/2

Step-by-step explanation:

perimeter = 2*(length + width)

53 m = 2*(2.3 m +w) . . . . an equation to find the width, w

26.5 m = 2.3 m +w . . . . . divide by 2

24.2 m = w . . . . . . . . . . . subtract 2.3 m

The width of the rectangle is 24.2 m

hope it helps

The width of the rectangle is 24.2 m

perimeter = 2*(length + width)

53 m = 2*(2.3 m +w) . . . . an equation to find the width, w

26.5 m = 2.3 m +w . . . . . divide by 2

24.2 m = w . . . . . . . . . . . subtract 2.3 m

The width of the rectangle is 24.2 m

i just took the test, the correct answer is .. 31.5 in.

2x + 8

step-by-step explanation: