Explain how complex fractions can be used to solve problems involving ratios

So when you have ratios, some are unknowns you have to create complex fractions from them. Bring to the same donominator, and solve for x.

Ex: we have this portion:
2 -x
5-45

and we change it into fractions 

2/5 =x/25

2x9/5x9 = x/45

answer would be 18=x

in case of more  complex fractions it may become in handy. 

Your welcome!!

A) for the n row: 22+(n-1)×6therefore,b) 100-22=78that means (n-1)×6=7878÷6=1313+1=1414th row has 100 seats

The answer is