Solve |2x - 2| < 8

a) { x| x < -3 or x > 5}

b) { x|-5 < x < 3}

c) { x|-3 < x < 5}

C

Step-by-step explanation:

|2x - 2| < 8

it implies that

2x - 2 < 8

2x -2 + 2 < 8 + 2

2x < 10

x < 5

or

-(2x - 2) < 8

-2x + 2 < 8

-2x + 2 - 2 < 8 - 2

- 2x < 6

x > -3 ( the sense of the inequality reverse because I divided by minus)

The solution can be combine to

-3<x<5