Given a system of linear equations; explain your strategy for solving the system, show the math required to solve the problem, and show the solution as an ordered pair.

y = 3x - 3

y = 2x - 1

The solution is (x, y) = (2, 3)

Solution:

Given equations are:

y = 3x - 3 eqn 1

y = 2x - 1 eqn 2

We can solve the equations by substitution method

In eqn 1, we have y equals 3x - 3

If we substitute this in place of y in eqn 2, we can get value of "x"

Substitute eqn 1 in eqn 2

3x - 3 = 2x - 1

Move the variables to one side and constants to other side

3x - 2x = -1 + 3

Substitute x = 2 in eqn 1

y = 3(2) - 3

y = 6 - 3

Thus the solution is (x, y) = (2, 3)

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!