if c (x) = startfraction 5 over x minus 2 endfraction and d(x) = x + 3, what is the domain of (cd)(x)?
all real values of x
all real values of x except x = 2
all real values of x except x = –3
all real values of x except x = 2 and x = –3

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are and d(x) = x + 3

So, (cd)(x) =

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

6 meters

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".