Can anyone answer this equation? ?
it's pretty hard. and i don't get it whatsoever.

The tangent of an angle is the ratio of the opposite over adjacent sides.

tan(angle) = opposite/adjacent

tan(theta) = 4/3

This means that

opposite = 4 and adjacent = 3

This only happens when angle P is the reference angle. In other words,

tan(P) = 4/3

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this