The data in the following table are particulate emissions for 65 vehicles, in units of grams of particles per gallon of fuel. construct
a frequency distribution using a class width of 0.75, and using 0.00 as the lower limit for the first class.
1.49 0.86 1.12 1.25 3.45 1.12 1.12 0.87 1.29 0.95 0.64 1.31 2.48
1.50 1.07 1.13 2.15 0.87 1.81 1.46 1.25 1.63 2.15 6.65 4.04 2.49
1.39 1.35 1.81 1.13 1.64 3.67 0.56 2.65 2.64 3.04 1.23 1.05 1.62
3.11 2.38 2.11 2.69 1.16 3.33 3.79 1.29 2.11 6.55 1.19 3.06 0.48
0.24 0.53 3.36 3,47 2.73 1.87 5.94 4.23 3.51 3.57 3.10 3.32 4.57

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.

good luck on ur quiz test or homework. have a good day : )