Aproper rectangle has a lengh of 6 inches and a with of 8 inches. a square with a side lenght of 3 inches was cut of it. what is the area of the remaining paper?

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = 2(L + W)

Where

L represents the length of the rectangle.

W represents the width of the rectangle.

A proper rectangle has a length of 6 inches and a with of 8 inches. The area of the rectangle would be

6 × 8 = 48 inches^2

A square with a side length of 3 inches was cut of it. The formula for determining the area of a square is l^2

Therefore,

Area of square = 3^2 = 9 inches ^2

The area of the remaining paper would be

48 - 9 = 39 inches^2

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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