Complete the function remove_all(l, x) so that, given a list l and a target value x, it returns a copy of the list that excludes all occurrences of x but preserves the order of the remaining elements.

Code is given below along with explanation and output.

Step-by-step explanation:

we can use the method of list comprehension to achieve the given task.

In a list comprehension, we create a sub-list of elements which satisfy specific conditions. the condition i !=x makes sure that x would be excluded in the modified list.

def remove_all(L, x):

   return [i for i in L if i != x]

L = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4 ]

print('Before =',L)

L = remove_all(L, 4)

print('After =',L)

Output:

Before = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4]

After = [1, 2, 3, 5, 6, 3, 2]

As you can see we have successfully removed the multiple occurrence of x=4 while preserving the order of the list.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.