Atriangle pqs such that angle psq=68°pq is ptoduced to r such that angle rqs=146° calculate the size of angle spq and sqr

(i) SPQ =

(ii) SQR = 146°

Step-by-step explanation:

<SPQ = 146 - 68 = ( the exterior angle of a triangle is equal to the sum of the two opposite interior angle )

RQS is the exterior angle

The opposite interior angles are PSQ and SPQ , from the theorem :

PSQ + SPQ = RQS , that is

68 + SPQ = 146

SPQ = 146 - 68

SPQ =

(ii) SQR = RQS

Therefore : SQR = 146°

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)