Megan started biking to the internet cafe traveling 9 mph, after some time the bike got a flat so megan walked the rest of the way, traveling 7 mph. if the total trip to the internet cafe took 9 hours and it was 75 miles away, how long did megan travel at each speed

Megan travelled at 9mph for 6 hours and 7mph for 3 hours

Step-by-step explanation:

Speed = distance / time

Speed*time = distance

Assuming that Megan travelled x hours at 9mph

(9*x) + (7*(9-x)) = 75

x = 6 hours

So Megan travelled at 9mph for 6 hours and 7mph for 3 hours

d=54 miles

Step-by-step explanation:

We let the distance megan covered =d

And the distance she walked to the cafe will be :

75 - d

Therefore

d/9 + (75 - d) / 7 =9

L.c.m is 63

7d+9(75-d)=63×9

7d+675-9d=567

-2d=567-675

d=108/2

d=54

d=54 miles

okay so 15.15 *()5: +5/6

step-by-step explanation:

b.-4 units

all you   do is count how many times you move