Shota built a time travel machine, but he can't control the duration of his trip. each time he uses the machine he has a 0.80.80, point, 8 probability of staying in the alternative time for more than an hour. during the first year of testing, shota uses his machine 202020 times. assuming that each trip is equally likely to last for more than an hour, what is the probability that at least one trip will last less than an hour?

0.988

Step-by-step explanation:

P(at least all trips last less than1 hour)=1-P(all trips last 1 hour or more)=

Therefore, the probability is 0.988  to three decimal places

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.