The graph of a quadratic function f has a vertex (-1,-10) and passes through the point (1,2). which of the following represents f in vertex form?

(y + 10)² = 72(x + 1)

Step-by-step explanation:

If we assume the vertex of the parabola is (α,β) and the axis is parallel to the positive x-axis, then its equation is given by

(y - β)² = 4a(x - α) (1)

Now, the vertex is (-1,-10).

So, the equation will become (y + 10)² = 4a(x + 1) (2)

Now, (1,2) is a point on the parabola.

So, equation (2) becomes (2 + 10)² = 4a(1 + 1)

⇒ 144 = 8a

⇒ 4a = 72

Therefore, the final equation of the parabola in vertex form will be

(y + 10)² = 72(x + 1) (Answer)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5