Write the equation of a line that is parallel to y= 3x-2 and that passes through (9,-5).

y = -1/3x + 2

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals.

The line y = 3x - 2 has slope 3.

The perpendicular line has slope -1/3.

Now we find the equation of the line that has slope -1/3 and passes through (-9, 5).

y = mx + b

y = -1/3x + b

5 = (-1/3)(-9) + b

5 = 3 + b

b = 2

The equation of the perpendicular is

y = -1/3x + 2

b. hannah is playing with her cousin at

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16