In a group of 55 people, 33 are coffee drinkers and 12 are tea drinkers. assuming that no one in this group drinks both tea and coffee, what is the probability that a person picked at random from the group does not drink tea or coffee?

Since the whole set is composed of a total of 55 people, with 45 people being drinks of either coffer or tea, then the remaining people not included in the 45 would be the non-drinkers. So 55-45, meaning there are 10 people who drink neither tea nor coffee. To obtain the probability:

10/55 = 2/11 = 0.182

Therefore, the probability of a person being picked at random does not drink either coffee or tea is 0.182.

The answer is 3 imbecause ur so cool dude